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Mohamed G. Gouda					CS 356
Spring 2017						Exercise 8
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Consider a router that has three interfaces 0, 1, and 2. Assume
that this router has the following routing table:

	--------------------------------------------------
	If dst of a pkt is in	| Then this pkt is routed
	this block ...		| to this interface ...
	--------------------------------------------------
	(128.64.255.9/26)	| 0
	--------------------------------------------------
	(128.64.255.60/30)	| 1
	--------------------------------------------------
	Otherwise		| 2
	--------------------------------------------------

How a pkt, whose ultimate dst is IP address (128.64.255.63),
is routed based on this routing table? Explain your answer.

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Solution
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A packet whose ultimate destination is (128.64.255.63) is in 
block (128.64.255.9/26) and is in block (128.64.255.60/30).
Therefore, this packet is routed to interface 1 because the
subnet mask (30) for interface 1 is longer than the subnetwork
mask (26) for interface 0.
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