Apply
(shr-values val1 val2) → resval
It is an error if the values are not integers. If they are integers, we promote them and then we call the operation on integer values.
Function:
(defun shr-values (val1 val2) (declare (xargs :guard (and (valuep val1) (valuep val2)))) (let ((__function__ 'shr-values)) (declare (ignorable __function__)) (if (and (value-integerp val1) (value-integerp val2)) (shr-integer-values (promote-value val1) (promote-value val2)) (error (list :shr-mistype :required :integer :integer :supplied (value-fix val1) (value-fix val2))))))
Theorem:
(defthm value-resultp-of-shr-values (b* ((resval (shr-values val1 val2))) (value-resultp resval)) :rule-classes :rewrite)
Theorem:
(defthm shr-values-of-value-fix-val1 (equal (shr-values (value-fix val1) val2) (shr-values val1 val2)))
Theorem:
(defthm shr-values-value-equiv-congruence-on-val1 (implies (value-equiv val1 val1-equiv) (equal (shr-values val1 val2) (shr-values val1-equiv val2))) :rule-classes :congruence)
Theorem:
(defthm shr-values-of-value-fix-val2 (equal (shr-values val1 (value-fix val2)) (shr-values val1 val2)))
Theorem:
(defthm shr-values-value-equiv-congruence-on-val2 (implies (value-equiv val2 val2-equiv) (equal (shr-values val1 val2) (shr-values val1 val2-equiv))) :rule-classes :congruence)