counters
stobj
Major Section: STOBJ
the event
(defstobj counters (NodeCnt :type integer :initially 0) (TipCnt :type integer :initially 0) (IntTipsSeen :type t :initially nil))discussed in stobj-example-1, creates a Common Lisp object to represent the current value of
counters
. That object is created
by evaluating either of the following ``raw'' (non-ACL2) Common Lisp
forms:
(create-counters) (vector (make-array 1 :element-type 'integer :initial-element '0) (make-array 1 :element-type 'integer :initial-element '0) 'nil)and the value is stored in the Common Lisp global variable named
*the-live-counters*
.
Thus, the counters
object is an array of length three. The first
two elements are arrays of size 1 and are used to hold the
NodeCnt
and TipCnt
fields. The third element is the
IntTipsSeen
field. The first two fields are represented by
arrays so that we can implement the integer
type specification
efficiently. Generally, integers are ``boxed'' in some Common Lisp
implementations, for example, GCL. Creating a new integer requires
creating a new box to put it in. But in some lisps, including GCL,
the integers inside arrays of integers are not boxed.
The function NodeCnt
is defined in raw Lisp as:
(defun NodeCnt (counters) (the integer (aref (the (simple-array integer (1)) (svref counters 0)) 0)))Observe that the form
(svref counters 0)
is evaluated to get
an array of size 1, which is followed by a call of aref
to
access the 0th element of that array.The function update-NodeCnt
is defined in raw Lisp as:
(defun update-NodeCnt (v counters) (declare (type integer v)) (progn (setf (aref (the (simple-array integer (1)) (svref counters 0)) 0) (the integer v)) counters))Note that when this function is called, it does not create a new vector of length three, but ``smashes'' the existing one.
One way to see all the raw Lisp functions defined by a given defstobj
is
to evaluate the defstobj
event and then evaluate, in the ACL2 loop, the
expression (nth 4 (global-val 'cltl-command (w state)))
. Those functions
that contain (DECLARE (STOBJ-INLINE-FN T))
will generate defabbrev
forms because the :inline
keyword of defstobj
was supplied the
value t
. The rest will generate defun
s.
We now recommend that you look at stobj-example-1-proofs.