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(transform '((- (- ?x ?y)) (- ?y ?x) )
         '(- (- (sin theta) z)) )

  • A: (- z (sin theta))
  • B: nil
  • C: (- (sin theta) z)
  • D: (- (- (sin theta) z))
  • E: (- (- z (sin theta)))

    Answer: A

    ?x matches (sin theta) and ?y matches z; these are then substituted into the output pattern (- ?y ?x).