Now (factorial 1) = 1 and our stack looks like:

n = 2

n = 3

We multiply 2 by the value of (factorial 1) and return 2 as the value of (factorial 2):

n = 3

We multiply 3 by the value of (factorial 2) and return 6 as the final value of (factorial 3). Now the stack is empty.

Look back at page trace to see how the trace printout shows the argument values and return values.

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