(let ((x 2) (y 3)) (let ((x 7) (z (+ x y))) (* z x)))The initial values in the inner let are evaluated ``simultaneously'' before the new variables are bound, so (+ x y) is evaluated with x = 2.= 35
(let ((x 2) (y 3)) (let* ((x 7) (z (+ x y))) (* z x)))= 70
The initial values in the inner let* are evaluated sequentially, so (+ x y) is evaluated with x = 7.
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