Answer: B
some is an or over a set of items: some(p, lst) = p(lst1) || p(lst2) || ... || p(lstn) = p(lst1) ∨ p(lst2) ∨ ... ∨ p(lstn) .
The base case (identity or idempotent value) for or is false, since (x || false) = x, so some should return false as its base case when the list is empty.